C++ Pointer to Integer with Increment Example

#include <iostream>

using namespace std;
int main() 
{
    int x = 7;
    int* ptr = &x;
    cout << *ptr << " ";
    (*ptr)++;
    cout << *ptr;
    return 0;
}

Answer: 7 8

Explanation:

• In this C++ code, an integer variable x is declared and initialized with the value 7.
• A pointer ptr is declared and initialized to store the address of x using the address-of operator (&).
• cout << *ptr << " "; prints the value pointed to by ptr, which is the value of x, i.e., 7. So, the first output is "7 ".
• (*ptr)++; increments the value stored at the memory location pointed to by ptr. In this case, it increases the value of x from 7 to 8.
• cout << *ptr; prints the updated value pointed to by ptr, which is now 8. So, the final output is "8".

This code demonstrates how a pointer can be used to access and modify the value of a variable indirectly.